Jeremy and Eric had 58 shortbreads altogether. After Jeremy ate
15 of his shortbreads and Eric ate 6 shortbreads, the number of shortbreads Eric had left was twice the number of shortbreads Jeremy had left. How many more shortbreads did Eric have than Jeremy at first?
|
Jeremy |
Eric |
Total |
Before |
5 u |
8 u + 6 |
58 |
Change |
- 1 u |
- 6 |
|
After |
4 u |
|
|
Comparing Jeremy and Eric in the end |
1x4 = 4 u |
2x4 = 8 u |
|
The number of shortbreads that Jeremy had in the end is the same. Make the number of shortbreads that Jeremy had in the end the same. LCM of 4 and 1 is 4.
Total number of shortbreads at first
= 5 u + 8 u + 6
= 13 u + 6
13 u + 6 = 58
13 u = 58 - 6
13 u = 52
1 u = 52 ÷ 13 = 4
Number of shortbreads that Jeremy had at first
= 5 u
= 5 x 4
= 20
Number of shortbreads that Eric had at first
= 58 - 20
= 38
Number of shortbreads that Eric had more than Jeremy at first
= 38 - 20
= 18
Answer(s): 18