Reggie and Perry had 48 cookies altogether. After Reggie ate
14 of his cookies and Perry ate 8 cookies, the number of cookies Perry had left was twice the number of cookies Reggie had left. How many more cookies did Perry have than Reggie at first?
|
Reggie |
Perry |
Total |
Before |
4 u |
6 u + 8 |
48 |
Change |
- 1 u |
- 8 |
|
After |
3 u |
|
|
Comparing Reggie and Perry in the end |
1x3 = 3 u |
2x3 = 6 u |
|
The number of cookies that Reggie had in the end is the same. Make the number of cookies that Reggie had in the end the same. LCM of 3 and 1 is 3.
Total number of cookies at first
= 4 u + 6 u + 8
= 10 u + 8
10 u + 8 = 48
10 u = 48 - 8
10 u = 40
1 u = 40 ÷ 10 = 4
Number of cookies that Reggie had at first
= 4 u
= 4 x 4
= 16
Number of cookies that Perry had at first
= 48 - 16
= 32
Number of cookies that Perry had more than Reggie at first
= 32 - 16
= 16
Answer(s): 16