Riordan and Asher had 86 biscuits altogether. After Riordan ate ¹₅ of his biscuits and Asher ate 8 biscuits, the number of biscuits Asher had left was twice the number of biscuits Riordan had left. How many more biscuits did Asher have than Riordan at first?

	Riordan	Asher	Total
Before	5 u	8 u + 8	86
Change	- 1 u	- 8
After	4 u
Comparing Riordan and Asher in the end	1x4 = 4 u	2x4 = 8 u

The number of biscuits that Riordan had in the end is the same. Make the number of biscuits that Riordan had in the end the same.  LCM of 4 and 1 is 4.

Total number of biscuits at first
= 5 u + 8 u + 8
= 13 u + 8

13 u + 8 = 86
13 u = 86 - 8
13 u = 78 

1 u = 78 ÷ 13 = 6

Number of biscuits that Riordan had at first
= 5 u
= 5 x 6
= 30

Number of biscuits that Asher had at first
= 86 - 30
= 56

Number of biscuits that Asher had more than Riordan at first
= 56 - 30
= 26

Answer(s): 26