Rael and Daniel had 42 wafers altogether. After Rael ate ¹₅ of his wafers and Daniel ate 3 wafers, the number of wafers Daniel had left was twice the number of wafers Rael had left. How many more wafers did Daniel have than Rael at first?

	Rael	Daniel	Total
Before	5 u	8 u + 3	42
Change	- 1 u	- 3
After	4 u
Comparing Rael and Daniel in the end	1x4 = 4 u	2x4 = 8 u

The number of wafers that Rael had in the end is the same. Make the number of wafers that Rael had in the end the same.  LCM of 4 and 1 is 4.

Total number of wafers at first
= 5 u + 8 u + 3
= 13 u + 3

13 u + 3 = 42
13 u = 42 - 3
13 u = 39 

1 u = 39 ÷ 13 = 3

Number of wafers that Rael had at first
= 5 u
= 5 x 3
= 15

Number of wafers that Daniel had at first
= 42 - 15
= 27

Number of wafers that Daniel had more than Rael at first
= 27 - 15
= 12

Answer(s): 12