Ryan and Vincent had 94 croissants altogether. After Ryan ate ¹₆ of his croissants and Vincent ate 10 croissants, the number of croissants Vincent had left was thrice the number of croissants Ryan had left. How many more croissants did Vincent have than Ryan at first?

	Ryan	Vincent	Total
Before	6 u	15 u + 10	94
Change	- 1 u	- 10
After	5 u
Comparing Ryan and Vincent in the end	1x5 = 5 u	3x5 = 15 u

The number of croissants that Ryan had in the end is the same. Make the number of croissants that Ryan had in the end the same.  LCM of 5 and 1 is 5.

Total number of croissants at first
= 6 u + 15 u + 10
= 21 u + 10

21 u + 10 = 94
21 u = 94 - 10
21 u = 84 

1 u = 84 ÷ 21 = 4

Number of croissants that Ryan had at first
= 6 u
= 6 x 4
= 24

Number of croissants that Vincent had at first
= 94 - 24
= 70

Number of croissants that Vincent had more than Ryan at first
= 70 - 24
= 46

Answer(s): 46