Elijah and Ryan had 28 biscuits altogether. After Elijah ate
13 of his biscuits and Ryan ate 7 biscuits, the number of biscuits Ryan had left was twice the number of biscuits Elijah had left. How many more biscuits did Ryan have than Elijah at first?
|
Elijah |
Ryan |
Total |
Before |
3 u |
4 u + 7 |
28 |
Change |
- 1 u |
- 7 |
|
After |
2 u |
|
|
Comparing Elijah and Ryan in the end |
1x2 = 2 u |
2x2 = 4 u |
|
The number of biscuits that Elijah had in the end is the same. Make the number of biscuits that Elijah had in the end the same. LCM of 2 and 1 is 2.
Total number of biscuits at first
= 3 u + 4 u + 7
= 7 u + 7
7 u + 7 = 28
7 u = 28 - 7
7 u = 21
1 u = 21 ÷ 7 = 3
Number of biscuits that Elijah had at first
= 3 u
= 3 x 3
= 9
Number of biscuits that Ryan had at first
= 28 - 9
= 19
Number of biscuits that Ryan had more than Elijah at first
= 19 - 9
= 10
Answer(s): 10