Simon and Liam received a total of $464. After Simon spent
56 of his money and Liam spent
45 of his money, Liam had 2 times as much money as Simon. How much money did Liam have at first?
| |
Simon |
Liam |
Total |
Before |
6 u |
5x2 =
10 u |
16 u |
Change |
- 5 u |
- 4x2 =
- 8 u |
|
After |
1 u |
1x2 =
2 u |
|
Comparing Simon
and Liam in the end |
1 u |
2 u |
|
The amount that Liam had in the end is the same. Make the amount that Liam had in the end the same. LCM of 1 and 2 is 2.
Total amount that Liam and Simon had at first
= 6 u + 10 u
= 16 u
16 u = 464
1 u = 464 ÷ 16 = 29
Amount that Liam had at first
= 10 u
= 10 x 29
= $290
Answer(s): $290
