Cole and Riordan received a total of $874. After Cole spent
78 of his money and Riordan spent
56 of his money, Riordan had 5 times as much money as Cole. How much money did Riordan have at first?
| |
Cole |
Riordan |
Total |
Before |
8 u |
6x5 =
30 u |
38 u |
Change |
- 7 u |
- 5x5 =
- 25 u |
|
After |
1 u |
1x5 =
5 u |
|
Comparing Cole
and Riordan in the end |
1 u |
5 u |
|
The amount that Riordan had in the end is the same. Make the amount that Riordan had in the end the same. LCM of 1 and 5 is 5.
Total amount that Riordan and Cole had at first
= 8 u + 30 u
= 38 u
38 u = 874
1 u = 874 ÷ 38 = 23
Amount that Riordan had at first
= 30 u
= 30 x 23
= $690
Answer(s): $690
