Dylan and David had $836 altogether. After Dylan spent
15 of his money and David spent
67 of his money, Dylan was left with twice as much money as David. How much money did David have at first?
| |
Dylan |
David |
Total |
| Before |
5x1 =
5 u |
7x2 =
14 u |
$836 |
| Change |
- 1x1 =
- 1 u |
- 6x2 =
- 12 u |
|
| After |
4x1 =
4 u |
1x2 =
2 u |
|
Comparing Dylan
and David in the end |
2x2 =
4 u |
1x2 =
2 u |
|
The amount that Dylan had in the end is repeated. Make the amount that Dylan had in the end the same. LCM of 4 and 2 is 4.
Total amount that Dylan and David had at first
= 5 u + 14 u
= 19 u
19 u = 836
1 u = 836 ÷ 19 = 44
Amount that David had at first
= 14 u
= 14 x 44
= $616
Answer(s): $616
