Peter and Ken had $2162 altogether. After Peter spent
15 of his money and Ken spent
78 of his money, Peter was left with thrice as much money as Ken. How much money did Ken have at first?
| |
Peter |
Ken |
Total |
| Before |
5x3 =
15 u |
8x4 =
32 u |
$2162 |
| Change |
- 1x3 =
- 3 u |
- 7x4 =
- 28 u |
|
| After |
4x3 =
12 u |
1x4 =
4 u |
|
Comparing Peter
and Ken in the end |
3x4 =
12 u |
1x4 =
4 u |
|
The amount that Peter had in the end is repeated. Make the amount that Peter had in the end the same. LCM of 4 and 3 is 12.
Total amount that Peter and Ken had at first
= 15 u + 32 u
= 47 u
47 u = 2162
1 u = 2162 ÷ 47 = 46
Amount that Ken had at first
= 32 u
= 32 x 46
= $1472
Answer(s): $1472
