Jenson had
12 as many stickers as Albert. Albert had
23 as many stickers as Hilda. After Jenson and Hilda gave 6 stickers to Albert, Albert had four times as many stickers as Jenson. Hilda then had the same number of stickers as Albert.
- What was the ratio of the number of stickers Jenson had to the number of stickers Hilda had in the beginning? Answer in simplest form.
- How many stickers did Albert have in the end?
Jenson |
Albert |
Hilda |
1 |
2 |
|
|
2 |
3 |
1 |
2 |
3 |
(a)
The number of stickers that Albert is repeated.
Ratio of the number of stickers that Jenson had to the number of stickers that Hilda had in the beginning = 1 : 3
|
Jenson |
Albert |
Hilda |
Total |
Before |
1x3 = 3 u |
2x3 = 6 u |
3x3 = 9 u |
6x3 = 18 u |
Change |
- 6 |
+ 12 |
- 6 |
|
After |
1x2 = 2 u |
4x2 = 8 u |
4x2 = 8 u |
9x2 = 18 u |
The total number of stickers at first and in the end remains unchanged. Make the total number of stickers the same. LCM of 6 and 9 is 18.
Number of stickers that Albert received from Jenson and Hilda
= 2 x 6
= 12
Number of stickers that Albert received from Jenson and Hilda
= 2 x 1 u
= 2 u
2 u = 6
1 u = 6 ÷ 2 = 3
Number of stickers that Ashley had in the end
= 8 u
= 8 x 3
= 24
Answer(s): (a) 1 : 3; (b) 24