Lee had ¹₂ as many coins as Henry. Henry had ²₃ as many coins as Risa. After Lee and Risa gave 16 coins to Henry, Henry had four times as many coins as Lee. Risa then had the same number of coins as Henry.

1. What was the ratio of the number of coins Risa had to the number of coins Lee had in the beginning? Answer in simplest form.
2. How many coins did Henry have in the end?

Lee	Henry	Risa
1	2
	2	3
1	2	3

(a)
The number of coins that Henry is repeated.  

Ratio of the number of coins that Risa had to the number of coins that Lee had in the beginning = 3 : 1

	Lee	Henry	Risa	Total
Before	1x3 = 3 u	2x3 = 6 u	3x3 = 9 u	6x3 = 18 u
Change	- 16	+ 32	- 16
After	1x2 = 2 u	4x2 = 8 u	4x2 = 8 u	9x2 = 18 u

The total number of coins at first and in the end remains unchanged. Make the total number of coins the same. LCM of 6 and 9 is 18.

Number of coins that Henry received from Lee and Risa
= 2 x 16
= 32

Number of coins that Henry received from Lee and Risa
= 2 x 1 u
= 2 u

2 u = 16

1 u = 16 ÷ 2 = 8

Number of coins that Ashley had in the end
= 8 u
= 8 x 8
= 64