Tom had ³₄ as many coins as Daniel. Daniel had ⁴₇ as many coins as Jaslyn. After Tom and Jaslyn gave 28 coins to Daniel, Daniel had thrice as many coins as Tom. Jaslyn then had the same number of coins as Daniel.

1. What was the ratio of the number of coins Jaslyn had to the number of coins Tom had in the beginning? Answer in simplest form.
2. How many coins did Daniel have in the end?

Tom	Daniel	Jaslyn
3	4
	4	7
3	4	7

(a)
The number of coins that Daniel is repeated.  

Ratio of the number of coins that Jaslyn had to the number of coins that Tom had in the beginning = 7 : 3

	Tom	Daniel	Jaslyn	Total
Before	3x1 = 3 u	4x1 = 4 u	7x1 = 7 u	14x1 = 14 u
Change	- 28	+ 56	- 28
After	1x2 = 2 u	3x2 = 6 u	3x2 = 6 u	7x2 = 14 u

The total number of coins at first and in the end remains unchanged. Make the total number of coins the same. LCM of 14 and 7 is 14.

Number of coins that Daniel received from Tom and Jaslyn
= 2 x 28
= 56

Number of coins that Daniel received from Tom and Jaslyn
= 2 x 1 u
= 2 u

2 u = 28

1 u = 28 ÷ 2 = 14

Number of coins that Ashley had in the end
= 6 u
= 6 x 14
= 84