Vaidev had ³₄ as many stamps as Jenson. Jenson had ⁴₇ as many stamps as Xuan. After Vaidev and Xuan gave 24 stamps to Jenson, Jenson had thrice as many stamps as Vaidev. Xuan then had the same number of stamps as Jenson.

1. What was the ratio of the number of stamps Vaidev had to the number of stamps Xuan had in the beginning? Answer in simplest form.
2. How many stamps did Jenson have in the end?

Vaidev	Jenson	Xuan
3	4
	4	7
3	4	7

(a)
The number of stamps that Jenson is repeated.  

Ratio of the number of stamps that Vaidev had to the number of stamps that Xuan had in the beginning = 3 : 7

	Vaidev	Jenson	Xuan	Total
Before	3x1 = 3 u	4x1 = 4 u	7x1 = 7 u	14x1 = 14 u
Change	- 24	+ 48	- 24
After	1x2 = 2 u	3x2 = 6 u	3x2 = 6 u	7x2 = 14 u

The total number of stamps at first and in the end remains unchanged. Make the total number of stamps the same. LCM of 14 and 7 is 14.

Number of stamps that Jenson received from Vaidev and Xuan
= 2 x 24
= 48

Number of stamps that Jenson received from Vaidev and Xuan
= 2 x 1 u
= 2 u

2 u = 24

1 u = 24 ÷ 2 = 12

Number of stamps that Ashley had in the end
= 6 u
= 6 x 12
= 72