Brandon and Xavier have a total of $210. If Brandon gives Xavier $47, they will each have an equal amount of money. How much money has each of them at first?
- Brandon
- Xavier
|
Brandon |
Xavier |
Total |
Before |
1 u + 47 |
1 u - 47 |
$210 |
Change |
- 47 |
+ 47 |
|
After |
1 u |
1 u |
$210 |
(a)
Total amount that Brandon and Xavier have in the end
= 1 u + 1 u
= 2 u
2 u = 210
1 u = 210 ÷ 2 = 105
Amount that Brandon has at first
= 1 u + 47
= 105 + 47
= $152
Amount that Xavier has at first
= 210 - 152
= $58
Answer(s): (a) $152; (b) $58