Marion and Barbara have 488 coins altogether. Barbara has thrice as many coins as Marion. How many coins must Barbara give to Marion so that they have the same number of coins?
| |
Marion |
Barbara |
Total |
| Before |
1 u |
3 u |
488 |
| Change |
+ ? |
- ? |
|
| After |
244 |
244 |
488 |
Total number of coins that Marion and Barbara have
= 1 u + 3 u
= 4 u
4 u = 488
1 u = 488 ÷ 4 = 122
Number of coins that Marion and Barbara each has in the end
= 488 ÷ 2
= 244
Number of coins that Barbara must give to Marion
= 244 - 122
= 122
Answer(s): 122
