Natalie and Marion have 224 coins altogether. Marion has thrice as many coins as Natalie. How many coins must Marion give to Natalie so that they have the same number of coins?
| |
Natalie |
Marion |
Total |
| Before |
1 u |
3 u |
224 |
| Change |
+ ? |
- ? |
|
| After |
112 |
112 |
224 |
Total number of coins that Natalie and Marion have
= 1 u + 3 u
= 4 u
4 u = 224
1 u = 224 ÷ 4 = 56
Number of coins that Natalie and Marion each has in the end
= 224 ÷ 2
= 112
Number of coins that Marion must give to Natalie
= 112 - 56
= 56
Answer(s): 56
