Jean and Xuan have 348 coins altogether. Xuan has thrice as many coins as Jean. How many coins must Xuan give to Jean so that they have the same number of coins?
| |
Jean |
Xuan |
Total |
| Before |
1 u |
3 u |
348 |
| Change |
+ ? |
- ? |
|
| After |
174 |
174 |
348 |
Total number of coins that Jean and Xuan have
= 1 u + 3 u
= 4 u
4 u = 348
1 u = 348 ÷ 4 = 87
Number of coins that Jean and Xuan each has in the end
= 348 ÷ 2
= 174
Number of coins that Xuan must give to Jean
= 174 - 87
= 87
Answer(s): 87
