Xylia and Min have 352 cards altogether. Min has thrice as many cards as Xylia. How many cards must Min give to Xylia so that they have the same number of cards?
| |
Xylia |
Min |
Total |
| Before |
1 u |
3 u |
352 |
| Change |
+ ? |
- ? |
|
| After |
176 |
176 |
352 |
Total number of cards that Xylia and Min have
= 1 u + 3 u
= 4 u
4 u = 352
1 u = 352 ÷ 4 = 88
Number of cards that Xylia and Min each has in the end
= 352 ÷ 2
= 176
Number of cards that Min must give to Xylia
= 176 - 88
= 88
Answer(s): 88
