Julie has some pens. She has 3 less pens in Bag C than in Bag D. After 12 pens were transferred from Bag D to Bag C, there were 58 pens in Bag D.
- How many pens were there in Bag D at first?
- How many pens were there in Bag C in the end?
|
Bag C |
Bag D |
Before |
1 u |
1 u + 3 |
Change |
+ 12 |
- 12 |
After |
1 u + 12 |
58 |
(a)
Number of pens in Bag D at first
= 58 + 12
= 70
(b)
Number of pens in Bag C at first
= 70 - 3
= 67
Number of pens in Bag C in the end
= 67 + 12
= 79
Answer(s): (a) 70; (b) 79