Ahmad and Liam have a total of $177. If Liam gives Ahmad $36, Ahmad will have twice as much money as Liam. How much money has each of them at first?
- Liam
- Ahmad
|
Ahmad |
Liam |
Total |
Before |
2 u - $36 |
1 u + $36 |
$177 |
Change |
+ $36 |
- $36 |
|
After |
2 u |
1 u |
$177 |
(a)
Total amount that Ahmad and Liam have in the end
= 1 u + 2 u
= 3 u
3 u = 177
1 u = 177 ÷ 3 = 59
Amount that Liam has at first
= 1 u + 36
= 59 + 36
= $95
(b)
Amount that Ahmad has at first
= 177 - 95
= $82
Answer(s): (a) $95; (b) $82