Xavier and Billy have a total of $270. If Billy gives Xavier $16, Xavier will have four times as much money as Billy. How much money has each of them at first?
- Billy
- Xavier
|
Xavier |
Billy |
Total |
Before |
4 u - $16 |
1 u + $16 |
$270 |
Change |
+ $16 |
- $16 |
|
After |
4 u |
1 u |
$270 |
(a)
Total amount that Xavier and Billy have in the end
= 1 u + 4 u
= 5 u
5 u = 270
1 u = 270 ÷ 5 = 54
Amount that Billy has at first
= 1 u + 16
= 54 + 16
= $70
(b)
Amount that Xavier has at first
= 270 - 70
= $200
Answer(s): (a) $70; (b) $200