Pierre and Kimberly shared some beads equally. After Kimberly bought 83 beads and Pierre gave 112 beads away, they had 481 beads left. How many beads did each of them have at first?
| |
Pierre |
Kimberly |
Total |
| Before |
1 u |
1 u |
|
| Change |
+ 83 |
- 112 |
|
| After |
1 u + 83 |
1 u - 112 |
481 |
Pierre and Kimberly had the same number of beads at first.
Total number of beads in the end
= 1 u + 83 + 1 u - 112
= 1 u + 1 u + 83 - 112
= 2 u - 29
2 u - 29 = 481
2 u = 481 + 29
2 u = 510
1 u = 510 ÷ 2 = 255
Number of beads that each of them had at first
= 1 u
= 255
Answer(s): 255
