Julian and Lynn shared some coins equally. After Lynn bought 68 coins and Julian gave 152 coins away, they had 142 coins left. How many coins did each of them have at first?
| |
Julian |
Lynn |
Total |
| Before |
1 u |
1 u |
|
| Change |
+ 68 |
- 152 |
|
| After |
1 u + 68 |
1 u - 152 |
142 |
Julian and Lynn had the same number of coins at first.
Total number of coins in the end
= 1 u + 68 + 1 u - 152
= 1 u + 1 u + 68 - 152
= 2 u - 84
2 u - 84 = 142
2 u = 142 + 84
2 u = 226
1 u = 226 ÷ 2 = 113
Number of coins that each of them had at first
= 1 u
= 113
Answer(s): 113
