Eric and Xylia shared some erasers equally. After Xylia bought 22 erasers and Eric gave 78 erasers away, they had 522 erasers left. How many erasers did each of them have at first?
| |
Eric |
Xylia |
Total |
| Before |
1 u |
1 u |
|
| Change |
+ 22 |
- 78 |
|
| After |
1 u + 22 |
1 u - 78 |
522 |
Eric and Xylia had the same number of erasers at first.
Total number of erasers in the end
= 1 u + 22 + 1 u - 78
= 1 u + 1 u + 22 - 78
= 2 u - 56
2 u - 56 = 522
2 u = 522 + 56
2 u = 578
1 u = 578 ÷ 2 = 289
Number of erasers that each of them had at first
= 1 u
= 289
Answer(s): 289
