Xylia and Ivory had the same number of sweets at first. After Xylia received another 27 sweets and Ivory gave away 33 sweets, Xylia had 4 times as many sweets as Ivory. How many sweets did each of them have at first?
| |
Xylia |
Ivory |
| Before |
4 u - 27 |
1 u + 33 |
| Change |
+ 27 |
- 33 |
| After |
4 u |
1 u |
Xylia and Ivory had the same number of sweets at first.
4 u - 27 = 1 u + 33
4 u - 1 u = 33 + 27
3 u = 60
1 u = 60 ÷ 3 = 20
Number of sweets that each of them at first
= 20 + 33
= 53
Answer(s): 53
