Gem and Eva had the same number of chocolate bars at first. After Gem received another 38 chocolate bars and Eva gave away 10 chocolate bars, Gem had 4 times as many chocolate bars as Eva. How many chocolate bars did each of them have at first?
| |
Gem |
Eva |
| Before |
4 u - 38 |
1 u + 10 |
| Change |
+ 38 |
- 10 |
| After |
4 u |
1 u |
Gem and Eva had the same number of chocolate bars at first.
4 u - 38 = 1 u + 10
4 u - 1 u = 10 + 38
3 u = 48
1 u = 48 ÷ 3 = 16
Number of chocolate bars that each of them at first
= 16 + 10
= 26
Answer(s): 26
