Seth and Bobby had an equal number of lollipops at first. Seth and Bobby ate 87 and 7 lollipops respectively. In the end, Bobby has five times as many lollipops as Seth. How many lollipops did each of them has at first?
| |
Seth |
Bobby |
| Before |
1 u + 87 |
5 u + 7 |
| Change |
- 87 |
- 7 |
| After |
1 u |
5 u |
Seth and Bobby had an equal number of lollipops at first.
5 u + 7 = 1 u + 87
5 u - 1 u = 87 - 7
4 u = 80
1 u = 80 ÷ 4 = 20
Number of lollipops that each of them had at first
= 1 u + 87
= 20 + 87
= 107
Answer(s): 107
