Sean and George had an equal number of candy canes at first. Sean and George ate 47 and 11 candy canes respectively. In the end, George has four times as many candy canes as Sean. How many candy canes did each of them has at first?
| |
Sean |
George |
| Before |
1 u + 47 |
4 u + 11 |
| Change |
- 47 |
- 11 |
| After |
1 u |
4 u |
Sean and George had an equal number of candy canes at first.
4 u + 11 = 1 u + 47
4 u - 1 u = 47 - 11
3 u = 36
1 u = 36 ÷ 3 = 12
Number of candy canes that each of them had at first
= 1 u + 47
= 12 + 47
= 59
Answer(s): 59
