Cody and Tim had an equal number of mochi balls at first. Cody and Tim ate 79 and 3 mochi balls respectively. In the end, Tim has five times as many mochi balls as Cody. How many mochi balls did each of them has at first?
| |
Cody |
Tim |
| Before |
1 u + 79 |
5 u + 3 |
| Change |
- 79 |
- 3 |
| After |
1 u |
5 u |
Cody and Tim had an equal number of mochi balls at first.
5 u + 3 = 1 u + 79
5 u - 1 u = 79 - 3
4 u = 76
1 u = 76 ÷ 4 = 19
Number of mochi balls that each of them had at first
= 1 u + 79
= 19 + 79
= 98
Answer(s): 98
