Michael and Ken had an equal number of mochi balls at first. Michael and Ken ate 45 and 6 mochi balls respectively. In the end, Ken has four times as many mochi balls as Michael. How many mochi balls did each of them has at first?
|
Michael |
Ken |
Before |
1 u + 45 |
4 u + 6 |
Change |
- 45 |
- 6 |
After |
1 u |
4 u |
Michael and Ken had an equal number of mochi balls at first.
4 u + 6 = 1 u + 45
4 u - 1 u = 45 - 6
3 u = 39
1 u = 39 ÷ 3 = 13
Number of mochi balls that each of them had at first
= 1 u + 45
= 13 + 45
= 58
Answer(s): 58