Jeremy and George had an equal number of candy canes at first. Jeremy and George ate 28 and 2 candy canes respectively. In the end, George has thrice as many candy canes as Jeremy. How many candy canes did each of them has at first?
| |
Jeremy |
George |
| Before |
1 u + 28 |
3 u + 2 |
| Change |
- 28 |
- 2 |
| After |
1 u |
3 u |
Jeremy and George had an equal number of candy canes at first.
3 u + 2 = 1 u + 28
3 u - 1 u = 28 - 2
2 u = 26
1 u = 26 ÷ 2 = 13
Number of candy canes that each of them had at first
= 1 u + 28
= 13 + 28
= 41
Answer(s): 41
