Seth and Will had an equal number of sweets at first. Seth and Will ate 22 and 12 sweets respectively. In the end, Will has thrice as many sweets as Seth. How many sweets did each of them has at first?
| |
Seth |
Will |
| Before |
1 u + 22 |
3 u + 12 |
| Change |
- 22 |
- 12 |
| After |
1 u |
3 u |
Seth and Will had an equal number of sweets at first.
3 u + 12 = 1 u + 22
3 u - 1 u = 22 - 12
2 u = 10
1 u = 10 ÷ 2 = 5
Number of sweets that each of them had at first
= 1 u + 22
= 5 + 22
= 27
Answer(s): 27
