Tommy and Lee had an equal number of mochi balls at first. Tommy and Lee ate 17 and 5 mochi balls respectively. In the end, Lee has thrice as many mochi balls as Tommy. How many mochi balls did each of them has at first?
| |
Tommy |
Lee |
| Before |
1 u + 17 |
3 u + 5 |
| Change |
- 17 |
- 5 |
| After |
1 u |
3 u |
Tommy and Lee had an equal number of mochi balls at first.
3 u + 5 = 1 u + 17
3 u - 1 u = 17 - 5
2 u = 12
1 u = 12 ÷ 2 = 6
Number of mochi balls that each of them had at first
= 1 u + 17
= 6 + 17
= 23
Answer(s): 23
