Oscar and Xavier had an equal number of mochi balls at first. Oscar and Xavier ate 38 and 8 mochi balls respectively. In the end, Xavier has four times as many mochi balls as Oscar. How many mochi balls did each of them has at first?
| |
Oscar |
Xavier |
| Before |
1 u + 38 |
4 u + 8 |
| Change |
- 38 |
- 8 |
| After |
1 u |
4 u |
Oscar and Xavier had an equal number of mochi balls at first.
4 u + 8 = 1 u + 38
4 u - 1 u = 38 - 8
3 u = 30
1 u = 30 ÷ 3 = 10
Number of mochi balls that each of them had at first
= 1 u + 38
= 10 + 38
= 48
Answer(s): 48
