Oscar and Eric had an equal number of mochi balls at first. Oscar and Eric ate 43 and 11 mochi balls respectively. In the end, Eric has five times as many mochi balls as Oscar. How many mochi balls did each of them has at first?
| |
Oscar |
Eric |
| Before |
1 u + 43 |
5 u + 11 |
| Change |
- 43 |
- 11 |
| After |
1 u |
5 u |
Oscar and Eric had an equal number of mochi balls at first.
5 u + 11 = 1 u + 43
5 u - 1 u = 43 - 11
4 u = 32
1 u = 32 ÷ 4 = 8
Number of mochi balls that each of them had at first
= 1 u + 43
= 8 + 43
= 51
Answer(s): 51
