Brandon and Michael had an equal number of sweets at first. Brandon and Michael ate 53 and 5 sweets respectively. In the end, Michael has four times as many sweets as Brandon. How many sweets did each of them has at first?
| |
Brandon |
Michael |
| Before |
1 u + 53 |
4 u + 5 |
| Change |
- 53 |
- 5 |
| After |
1 u |
4 u |
Brandon and Michael had an equal number of sweets at first.
4 u + 5 = 1 u + 53
4 u - 1 u = 53 - 5
3 u = 48
1 u = 48 ÷ 3 = 16
Number of sweets that each of them had at first
= 1 u + 53
= 16 + 53
= 69
Answer(s): 69
