Simon and Paul had an equal number of sweets at first. Simon and Paul ate 31 and 15 sweets respectively. In the end, Paul has thrice as many sweets as Simon. How many sweets did each of them has at first?
| |
Simon |
Paul |
| Before |
1 u + 31 |
3 u + 15 |
| Change |
- 31 |
- 15 |
| After |
1 u |
3 u |
Simon and Paul had an equal number of sweets at first.
3 u + 15 = 1 u + 31
3 u - 1 u = 31 - 15
2 u = 16
1 u = 16 ÷ 2 = 8
Number of sweets that each of them had at first
= 1 u + 31
= 8 + 31
= 39
Answer(s): 39
