Julian and Simon had an equal number of mochi balls at first. Julian and Simon ate 40 and 2 mochi balls respectively. In the end, Simon has thrice as many mochi balls as Julian. How many mochi balls did each of them has at first?
| |
Julian |
Simon |
| Before |
1 u + 40 |
3 u + 2 |
| Change |
- 40 |
- 2 |
| After |
1 u |
3 u |
Julian and Simon had an equal number of mochi balls at first.
3 u + 2 = 1 u + 40
3 u - 1 u = 40 - 2
2 u = 38
1 u = 38 ÷ 2 = 19
Number of mochi balls that each of them had at first
= 1 u + 40
= 19 + 40
= 59
Answer(s): 59
