Tommy and Daniel had an equal number of mochi balls at first. Tommy and Daniel ate 44 and 4 mochi balls respectively. In the end, Daniel has thrice as many mochi balls as Tommy. How many mochi balls did each of them has at first?
| |
Tommy |
Daniel |
| Before |
1 u + 44 |
3 u + 4 |
| Change |
- 44 |
- 4 |
| After |
1 u |
3 u |
Tommy and Daniel had an equal number of mochi balls at first.
3 u + 4 = 1 u + 44
3 u - 1 u = 44 - 4
2 u = 40
1 u = 40 ÷ 2 = 20
Number of mochi balls that each of them had at first
= 1 u + 44
= 20 + 44
= 64
Answer(s): 64
