Seth and Bobby had an equal number of mochi balls at first. Seth and Bobby ate 51 and 3 mochi balls respectively. In the end, Bobby has five times as many mochi balls as Seth. How many mochi balls did each of them has at first?
| |
Seth |
Bobby |
| Before |
1 u + 51 |
5 u + 3 |
| Change |
- 51 |
- 3 |
| After |
1 u |
5 u |
Seth and Bobby had an equal number of mochi balls at first.
5 u + 3 = 1 u + 51
5 u - 1 u = 51 - 3
4 u = 48
1 u = 48 ÷ 4 = 12
Number of mochi balls that each of them had at first
= 1 u + 51
= 12 + 51
= 63
Answer(s): 63
