Julian and Cody had an equal number of sweets at first. Julian and Cody ate 49 and 10 sweets respectively. In the end, Cody has four times as many sweets as Julian. How many sweets did each of them has at first?
| |
Julian |
Cody |
| Before |
1 u + 49 |
4 u + 10 |
| Change |
- 49 |
- 10 |
| After |
1 u |
4 u |
Julian and Cody had an equal number of sweets at first.
4 u + 10 = 1 u + 49
4 u - 1 u = 49 - 10
3 u = 39
1 u = 39 ÷ 3 = 13
Number of sweets that each of them had at first
= 1 u + 49
= 13 + 49
= 62
Answer(s): 62
