Luke and Paul had an equal number of chocolate bars at first. Luke and Paul ate 76 and 12 chocolate bars respectively. In the end, Paul has five times as many chocolate bars as Luke. How many chocolate bars did each of them has at first?
| |
Luke |
Paul |
| Before |
1 u + 76 |
5 u + 12 |
| Change |
- 76 |
- 12 |
| After |
1 u |
5 u |
Luke and Paul had an equal number of chocolate bars at first.
5 u + 12 = 1 u + 76
5 u - 1 u = 76 - 12
4 u = 64
1 u = 64 ÷ 4 = 16
Number of chocolate bars that each of them had at first
= 1 u + 76
= 16 + 76
= 92
Answer(s): 92
