Will and Carl had an equal number of sweets at first. Will and Carl ate 32 and 8 sweets respectively. In the end, Carl has four times as many sweets as Will. How many sweets did each of them has at first?
| |
Will |
Carl |
| Before |
1 u + 32 |
4 u + 8 |
| Change |
- 32 |
- 8 |
| After |
1 u |
4 u |
Will and Carl had an equal number of sweets at first.
4 u + 8 = 1 u + 32
4 u - 1 u = 32 - 8
3 u = 24
1 u = 24 ÷ 3 = 8
Number of sweets that each of them had at first
= 1 u + 32
= 8 + 32
= 40
Answer(s): 40
