Mark and Liam had an equal number of lollipops at first. Mark and Liam ate 56 and 12 lollipops respectively. In the end, Liam has five times as many lollipops as Mark. How many lollipops did each of them has at first?
| |
Mark |
Liam |
| Before |
1 u + 56 |
5 u + 12 |
| Change |
- 56 |
- 12 |
| After |
1 u |
5 u |
Mark and Liam had an equal number of lollipops at first.
5 u + 12 = 1 u + 56
5 u - 1 u = 56 - 12
4 u = 44
1 u = 44 ÷ 4 = 11
Number of lollipops that each of them had at first
= 1 u + 56
= 11 + 56
= 67
Answer(s): 67
