Howard and Henry had an equal number of sweets at first. Howard and Henry ate 47 and 7 sweets respectively. In the end, Henry has thrice as many sweets as Howard. How many sweets did each of them has at first?
| |
Howard |
Henry |
| Before |
1 u + 47 |
3 u + 7 |
| Change |
- 47 |
- 7 |
| After |
1 u |
3 u |
Howard and Henry had an equal number of sweets at first.
3 u + 7 = 1 u + 47
3 u - 1 u = 47 - 7
2 u = 40
1 u = 40 ÷ 2 = 20
Number of sweets that each of them had at first
= 1 u + 47
= 20 + 47
= 67
Answer(s): 67
