Andy and Gabriel had an equal number of mochi balls at first. Andy and Gabriel ate 31 and 13 mochi balls respectively. In the end, Gabriel has four times as many mochi balls as Andy. How many mochi balls did each of them has at first?
| |
Andy |
Gabriel |
| Before |
1 u + 31 |
4 u + 13 |
| Change |
- 31 |
- 13 |
| After |
1 u |
4 u |
Andy and Gabriel had an equal number of mochi balls at first.
4 u + 13 = 1 u + 31
4 u - 1 u = 31 - 13
3 u = 18
1 u = 18 ÷ 3 = 6
Number of mochi balls that each of them had at first
= 1 u + 31
= 6 + 31
= 37
Answer(s): 37
