Sean and Andy had an equal number of candy canes at first. Sean and Andy ate 54 and 9 candy canes respectively. In the end, Andy has four times as many candy canes as Sean. How many candy canes did each of them has at first?
| |
Sean |
Andy |
| Before |
1 u + 54 |
4 u + 9 |
| Change |
- 54 |
- 9 |
| After |
1 u |
4 u |
Sean and Andy had an equal number of candy canes at first.
4 u + 9 = 1 u + 54
4 u - 1 u = 54 - 9
3 u = 45
1 u = 45 ÷ 3 = 15
Number of candy canes that each of them had at first
= 1 u + 54
= 15 + 54
= 69
Answer(s): 69
