Simon had 4 times as many brown markers as yellow markers. After giving away 10 brown markers and buying another 11 yellow markers, he had an equal number of brown and yellow markers. How many brown markers did Simon have at first?
| |
Brown markers |
Yellow markers |
| Before |
4 u |
1 u |
| Change |
- 10 |
+ 11 |
| After |
4 u - 10 |
1 u + 11 |
The number of brown and yellow markers is the same in the end.
4 u - 10 = 1 u + 11
4 u - 1 u = 11 + 10
3 u = 10 + 11
3 u = 21
1 u = 21 ÷ 3 = 7
Number of brown markers that Simon had at first
= 4 u
= 4 x 7
= 28
Answer(s): 28
