Lee had 4 times as many gold staplers as red staplers. After giving away 4 gold staplers and buying another 2 red staplers, he had an equal number of gold and red staplers. How many gold staplers did Lee have at first?
| |
Gold staplers |
Red staplers |
| Before |
4 u |
1 u |
| Change |
- 4 |
+ 2 |
| After |
4 u - 4 |
1 u + 2 |
The number of gold and red staplers is the same in the end.
4 u - 4 = 1 u + 2
4 u - 1 u = 2 + 4
3 u = 4 + 2
3 u = 6
1 u = 6 ÷ 3 = 2
Number of gold staplers that Lee had at first
= 4 u
= 4 x 2
= 8
Answer(s): 8
